X^2-3x+2x=4x^2

Solution for X^2-3x+2x=4x^2 equation:

X^2-3X+2X=4X^2

We move all terms to the left:

X^2-3X+2X-(4X^2)=0

determiningTheFunctionDomain
X^2-4X^2-3X+2X=0

We add all the numbers together, and all the variables

-3X^2-1X=0

a = -3; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-3)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-3}=\frac{0}{-6}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-3}=\frac{2}{-6}
=-1/3
$